# Thermodynamics — rankine cycles Essay Example

The step involved in simple cycle are as shown in the figure 1 1. Ideal simple cycle

At 170 bar and 600 we have the following results

160 bar, h =3573 s=6.64

180bar h=3556 s=6.57

Calculating h4 S4=6.64-0.5(0.64-6.57)

Calculating h5

At 0.065bar

Tempe=36.15 hf=151.5 hg=2567 sf=0.521 sg=8.331 Therefore Hence Now work    Net work output Heat input = But      Efficiency 1. With isentropic efficiency

At 90% turbine efficiency At 85% pump efficiency Hence net work output=1385.18-19.98

Heat input But  New efficiency Reheat cycle

The reheat cycle is as shown in figure 2 1. Ideal reheat cycle

Just as in the ideal simple cycle we have

At 170 bar and 600 we have the following results

160 bar, h =3573 s=6.64

180bar h=3556 s=6.57

Calculating h4 S4=6.64-0.5(0.64-6.57)

Calculating h5

Tempe=212.4 hf=908.8 hg=2800 sf=2.447 sg=6.341 Hence  As 6 and 5 are on the same isobar of 20 bar

From tables we have h6=3690kj/kg s6=7.702

At P =0.065bar

Tempe=36.15 hf=151.5 hg=2567 sf=0.521 sg=8.331

S6=s7=7.0702

The quality of steam at 7 Hence  Net work output   Heat input =    Efficiency 1. Reheat cycle with isentropic efficiencies

At 90% turbine efficiency  At 85% pump efficiency Hence net work output w=742.05+1193.22-19.98=1915.29

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