Industrial System Simulation 2 Essay Example

Pick time mean= 45min

Weighing mean time = 6min

p(x<20) = e-20/45

p(x<20) = e-20/6

= 0.03567

Total probability = 0.03567 * 0.641

= 0.02287

F-1(p) = — m ln(U)

y-1 =- m ln(U)

y-1 = — 0.641ln (U)

The graph from the above is

Industrial System Simulation 2

Industrial System Simulation 2  1

Data is in the attached excel sheet

Exponential mean for picking =45min

Exponential mean of weighing = 5min

Normal distribution = 1min

Standard deviation = 0.25min

λ1=1/45

p(x<20)=e-20/45

P(x>5) = e-20/5

From normal distribution table, with sd of 0.25 p(x>1)= 0.5987

Total probability

P(x>20)= 0.641 * 0.018*0.5987

p(x<60)=e-60/45

P(x>5) = e-60/5

= 0.0000061

From normal distribution table, with sd of 0.25 p(x>1)= 0.5987

p(x<60)= 0.265* 0.000006*0.5987

= 0.00000097

Industrial System Simulation 2  2

P(n>5000)= e(-1000/800)*0.05

  1. From z distribution table mean = -3.1

Y=f(x)=1-e-x/3.1

Inserting log on both sides

Log(1-y)=-x/3.1

Radom variables generated are as shown

0.141848

0.300421

0.480196

0.687731

0.933193

1.233614

1.620924

2.166807

The simulation

Industrial System Simulation 2  3

Industrial System Simulation 2  4

Mean =-6.2

Log(1-y)=-x/6.2

exponential

0.283696

0.600842

0.960392

1.375462

1.866386

2.467228

3.241848

4.333614

Industrial System Simulation 2  5

Industrial System Simulation 2  6