DESIGN AND DEVELOPMENT; BEARING SELECTION AND DESIGN Essay Example

Bearing Selection and Design

Bearing Selection and Design

Bearing Selection and Design

Considering the loading from the gear;

Taking moment about bearing A, then the reactions at the bearing supports will be obtained as follows.

Vertical loading

Bearing Selection and Design

Giving Bearing Selection and Design 1= 2.33KN

And summing vertical forces, then —Bearing Selection and Design 2-2.33+7=0

Giving Bearing Selection and Design 3= 4.66KN

In the Horizontal direction each bearing offers an equal amount of reaction giving an aggregate of 3KN

Thus Bearing Selection and Design 4= 1.5KN and Bearing Selection and Design 5=1.5KN

Combined reactions at bearings;

= 2.7736KNBearing Selection and Design 6A =

= 4.90213KNBearing Selection and Design 7B=

Equivalent radial loads are obtained as follows;Bearing Selection and Design 8

Where; W= basic dynamic equivalent radial loads

X= radial load factor and is equal to 1

Y= axial load factor and is equal to 0 since there is no thrust loading

V= rotational factor which is equal to 1 as the inner race is rotating

Bearing Selection and Design 9= constant axial load

Bearing Selection and Design 10= constant radial load

Equivalent radial load at bearing B= Bearing Selection and Design 11KN

If the expected life for 90% of the bearing is 1500 hours and taking a load factor as 1 at steady state condition,

Bearing Selection and Design 12

N is obtained from the equation Bearing Selection and Design 13

Where V= Bearing Selection and Design 14

33m/s =Bearing Selection and Design 15

Bearing Selection and Design 16= Bearing Selection and Design 17

N=1273revs

Bearing Selection and Design 18= 114.5767Bearing Selection and Design 19

Basic dynamic load rating, C,= Bearing Selection and Design 20

Where; k=3 for roller bearings

C=4.90213Bearing Selection and Design 21 114.57671/3Bearing Selection and Design 221= 23.8095KN

From SKF tables we select the bearing code 6210

2. If bearing no. 61810 is selected, the value of Basic dynamic load rating ,C, from the tables is 6.76KN

L=Bearing Selection and Design 233Bearing Selection and Design 24

L=Bearing Selection and Design 253Bearing Selection and Design 26

L=2.6223Bearing Selection and Design 27 and this is life at 90% reliability

life at 99% reliability will be obtained as follows;

Bearing Selection and Design 28

Considering life adjustment factors for operating condition and material as 0.9 and 0.85 respectively and their product equal to Bearing Selection and Design 29

b are constants whose value is 1.17

Bearing Selection and Design 30=0.1026

Bearing Selection and Design 31=0.1026Bearing Selection and Design 322.6223Bearing Selection and Design 33

=0.26905Bearing Selection and Design 34

Bearing Selection and Design 35

0.26905Bearing Selection and Design 3660Bearing Selection and Design 371273 Bearing Selection and Design 38

Bearing Selection and Design 39=3.5223 hours

ii. Expected life in km

Speed= 120km/h

Life= 120km/hBearing Selection and Design 403.5223

=422.68km

3. Life of bearing B= life of bearing A= 114.5767Bearing Selection and Design 41

C= Bearing Selection and Design 42

C= Bearing Selection and Design 43

C= 13.47KN

From SKF table the bearing selected is with the code 61910

4. It’s an overestimate, the reason being that the bearing selection and force application is considered at 99% reliability