CONNECTION PART = the part is Essay Example

Connection of beam

Buckling takes place when struts stiffness becomes zero and can no longer carry any load as shown. To avoid buckling on beam to beam connection the following connection is proposed.

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_f94eee45fd023ec4.png» vspace=»1″ alt=»CONNECTION PART = the part is «>

The beam to beam connection will use Pinned-Fixed Ends where the end will be fixed using bolts. It will 90o to the column but it will have a 45 degrees support to make strong. The lateral force will be equal to loading force to avoid buckling which can be very dangerous to the infrastructure under construction. The final outlook of the connection will be as follows;

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_419d909e2208bcb6.png» hspace=»1″ vspace=»1″ alt=»CONNECTION PART = the part is 1″>

In the beam to beam calculation of Buckling Load (N) for Pinned-Fixed Ends

Pe=<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_3b316ef8aa534eea.gif» alt=»CONNECTION PART = the part is 2″>

Where;Pe = Euler buckling load (N)

E = Young’s Modulus (Nm-2)

I = Second moment of area ( m4)

L = length of strut ( m )

Pe=<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_3b316ef8aa534eea.gif» alt=»CONNECTION PART = the part is 3″>

WORKINGS

Pe=<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_ded34672a3f8feda.gif» alt=»CONNECTION PART = the part is 4″> = 537.35

Pe=<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_234b2da666c97f80.gif» alt=»CONNECTION PART = the part is 5″> = 302.26

Pe=<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_ccfc21510310d355.gif» alt=»CONNECTION PART = the part is 6″> = 394.79

Pinned-Fixed Ends — Experimental Values

Beam length(m)

Buckling load(N)

2nd Moment of area(x10-9 m4)

Material(GPa)

Buckling Load (N) Theory

Looking at bolts

Shear capacity of bolts to be used in beams

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_d230be8921eef88c.gif» alt=»CONNECTION PART = the part is 7″>

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_2af8ed77bc8ac4a3.gif» alt=»CONNECTION PART = the part is 8″>=2,546

Resistance

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_a5d94fa77246d295.gif» alt=»CONNECTION PART = the part is 9″>

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_c38e754256618d8.gif» alt=»CONNECTION PART = the part is 10″>= 73.49kN

To decrease this stress, it is advised to use a bolt to distribute the stresses. To know which bolt would be most reasonable for this application, certain calculations are needed as shown below:

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_8e351d61a5e841e3.gif» alt=»CONNECTION PART = the part is 11″>

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_936f39696ea73609.gif» alt=»CONNECTION PART = the part is 12″>

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_b0f75f017bb003db.gif» alt=»CONNECTION PART = the part is 13″>

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_ba239fa03280fdf0.gif» alt=»CONNECTION PART = the part is 14″>

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_fe967cf34be75544.gif» alt=»CONNECTION PART = the part is 15″>

A specification sheet card is available as shown below
<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_8405d61564296372.png» hspace=»1″ alt=»CONNECTION PART = the part is 16″>

Figure 39 Specification Sheet Card

Pin Calculations

Pin Calculations- the pin size and load is calculated as shown below:

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_2d012f43e2608199.gif» alt=»CONNECTION PART = the part is 17″>Where F = 780 kN and  = 300 MPa

<img src=»/wp-content/uploads/2021/02/file_fore_convert_html_b3a412926c30b453.gif» alt=»CONNECTION PART = the part is 18″><img src=»/wp-content/uploads/2021/02/file_fore_convert_html_ad65cdb3124a9d9b.gif» alt=»CONNECTION PART = the part is 19″>